If 50.75 g of a gas occupies 10.0 l
Web3 apr. 2024 · If 50.75g of a gas occupies 10.0 L at STP, 129.3 g of a gas will occupy _____ L at STP.? September 23, 2024 April 3, 2024 by Answer Prime. 10L x 2.55 = 25.5L. ... “equal volumes of gases on the similar temperature and strain include the identical variety of molecules no matter their chemical nature and bodily properties ... WebQ: If 50.75 g of a gas occupies 10.0L at STP, 129.3 g of the same gas will occupy what volume at STP?… A: Click to see the answer Q: The volume of a gas is 1.50 L at 30.0°C and 1.00 atm. What volume will the gas occupy if the… A: V1= 1.50L T1= 30°C= (30+273)K=303K Pressure =1 atm T2=134.0°C= (134+273)K=407K V2=?
If 50.75 g of a gas occupies 10.0 l
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WebCHM 111 Gas Laws-Chapter 11 A gas occupies a volume of 3.86 L at 0.750 atm. At what pressure will the volume be 4.86 L. 1) A 4.50 L container of nitrogen gas at 28.0oC is heated to 56.0oC. Assuming the volume of the container can vary, what is the... Web13 mrt. 2024 · If 50.75 g of a gas occupies 10.0 L at STP, what volume will 129.3 g of the gas occupy at STP? 3.92 L 5.08 L 12.9L 25.5L 50.8 L Answer + 20 Watch For unlimited access to Homework Help, a Homework+ subscription is required. Lelia Lubowitz Lv2 13 Mar 2024 Unlock all answers Get 1 free homework help answer. Already have an …
WebIf 50.75 g of a gas occupies 10.0 L at STP, 129.3 g of the gas will occupy ________ L at STP. A) 3.92 B) 50.8 C) 12.9 D) 25.5 E) 5.08 D) 25.5 A sample of H2 gas (12.28 g) … Web18 nov. 2024 · If 50.75 g of a gas occupies 10.0 L at STP, 129.3 g of the gas will occupy L at STP. 20. 25.5 L -. Posted 11 months ago. Q: At standard conditions, 3.56 L of a gas …
WebIf 50.75 g of a gas occupies 10.0 L at STP, 129.3 g of the gas will occupy how many L at STP? Ideal Gas Equation: In chemistry and physics, the ideal gas equation models the... Web6 okt. 2024 · What is the molar mass of each of the following gases? 1) 0.78 g of a gas that occupies 500 mL at and 1.00 atm (STP).. 2) 1.42 g of a gas that occupies 1.15 L at and 760 mmHg (STP).. 3) 1.57 g of a gas that occupies 1.25 L at 680 mmHg and .
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WebQuestions and Answers for [Solved] If 50.75 g of a gas occupies 10.0 L at STP, 129.3 g of the gas will occupy L at STP. A) 50.8 B) 25.5 C) 5.08 D) 12.9 E) 3.92. Study Any Topic, Anywhere! The biggest database of online academic Questions & Answers is in your hands! jargon suffix wsjWeb3 apr. 2024 · If 50.75g of a gas occupies 10.0 L at STP, 129.3 g of a gas will occupy _____ L at STP.? September 23, 2024 April 3, 2024 by Answer Prime. 10L x 2.55 = 25.5L. ... “equal volumes of gases on the identical temperature and stress include the identical variety of molecules no matter their chemical nature and bodily properties ... jargons refers toWeb3 nov. 2024 · That’s the higher mass, the more the gas molecules, the greater the volume under constant temperature and pressure. 25.4. all you do is divide 129.3 by 50.75. Then multiply what you get by 10.0. this a ratio. 129.3 ÷ 50.75 = 2.55 10L x 2.55 = 25.5L. Leave a Reply Cancel reply Your email address will not be published. Required fields are marked * jargons of your fieldWeb15 jul. 2024 · 129.3 × 50.75 = 2.55 10L x 2.55 = 25.5L. 25.4. all you do is divide 129.3 by 50.75. Then multiply what you get by 10.0. it is a ratio. This question is a typical question based on Avogadro’s Law: jargons of businessWeb29 jun. 2024 · 50.75g/10L*22.4L/1 mol= 113.68g/mol- this is the molar weight of your gas 1mol/113.68g*129.3g=1.137403mol Configure an image format 1.137403mol/x L=1mol/22.4L X=25.477827L, or with sig digits, x=25.5L Source(s): Ap chem! It’s been a while since I’ve done chemistry. Since the gas is at STP, I would multiply 123.9 by 10.0 … low glycemic load breakfast ideasWebIf 50.75 g of a gas occupies 10.0 L at STP, 129.3 g of the gas will occupy how many L at STP? Ideal Gas Equation: In chemistry and physics, the ideal gas equation models the … low glycemic load indian foodsWebIf 50.75 g of a gas occupies 10.0 L at STP, 129.3 g of the gas L at STP. will occupy Select one: a. 2.55 b. 25.5 c. 51.0 d. 12.9 This problem has been solved! You'll get a detailed … jargons of medicine